19.9.26

Diagrammatic & Graphical Data Interpretation – APPSC Numerical Problems, Shortcuts & Practice Questions

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Diagrammatic & Graphical Data Interpretation – APPSC Numerical Problems, Shortcuts & Practice Questions

APPSC Statistics questionsలో graph లేదా diagramను కేవలం identify చేయడం మాత్రమే కాకుండా, ఇచ్చిన graphical data నుండి percentage, ratio, difference, average, sector angle, frequency density, cumulative frequency, median వంటి valuesను calculate చేయాల్సి ఉంటుంది.

ఈ Practice Chapterలో:

✓ Bar Graph Numericals
✓ Multiple Bar Graph Data Interpretation
✓ Component Bar Problems
✓ Pie Chart Numericals
✓ Histogram Problems
✓ Unequal Class Interval Problems
✓ Frequency Polygon Problems
✓ Ogive Problems
✓ Line Graph / Time-Series Problems
✓ Graph Selection Questions
✓ Mixed APPSC Data Interpretation Sets
✓ Fast Calculation Shortcuts
PART–A: Simple Bar Graph Numerical Problems

Bar graph questionsలో సాధారణంగా maximum, minimum, difference, ratio, average, percentage increase/decrease అడుగుతారు.

Problem 1 – Basic Bar Data Interpretation
A bar graph represents the number of candidates selected from five districts:
District Selected Candidates
A120
B180
C150
D210
E240

Q1. Which district has the highest number of selected candidates?

Answer: District E = 240

Q2. What is the difference between District E and District A?

240 − 120 = 120
Answer: 120 candidates

Q3. Find the ratio of candidates selected from B and D.

180 : 210 = 6 : 7
Answer: 6 : 7

Q4. Find the total number of selected candidates.

120 + 180 + 150 + 210 + 240 = 900
Answer: 900

Q5. Find the average number selected per district.

Average = 900 / 5 = 180
Answer: 180 candidates
⚡ Bar Graph Quick Attack:

Difference → Larger − Smaller

Ratio → First : Second → simplify

Average → Total / Number of Categories

Percentage → Part / Total × 100
Problem 2 – Percentage Increase
Production increased from 160 tonnes in 2024 to 200 tonnes in 2025. Find the percentage increase.
Increase = 200 − 160 = 40
Percentage Increase = (40 / 160) × 100
Answer: 25%
APPSC Trap:

Percentage increase denominator = Original Value, not new value.
PART–B: Multiple Bar Graph Problems
Problem 3 – Imports and Exports
Year Imports Exports
2021120100
2022150130
2023180160
2024200220
2025240260

Q1. In which year were exports greater than imports for the first time?

Answer: 2024

Q2. Find total imports during 2021–2025.

120 + 150 + 180 + 200 + 240 = 890
Answer: 890

Q3. Find total exports.

100 + 130 + 160 + 220 + 260 = 870
Answer: 870

Q4. By what percentage did exports increase from 2021 to 2025?

Increase = 260 − 100 = 160
Percentage Increase = (160/100) × 100 = 160%
Answer: 160%
PART–C: Component Bar Problems
Problem 4 – Family Expenditure
A family's monthly expenditure of ₹40,000 is represented by a component bar:
Item Expenditure (₹)
Food12,000
Rent10,000
Education8,000
Transport4,000
Others6,000

Q1. What percentage is spent on food?

12000 / 40000 × 100 = 30%
Answer: 30%

Q2. What percentage is spent on Rent + Education?

10000 + 8000 = 18000
18000 / 40000 × 100 = 45%
Answer: 45%

Q3. Find the ratio Food : Education.

12000 : 8000 = 3 : 2
Answer: 3 : 2
PART–D: Pie Chart – Most Important Numerical Area
Three Golden Formulas
Angle = (Component / Total) × 360°
Percentage = Angle / 3.6
Component Value = (Angle / 360°) × Total
Problem 5 – Percentage to Angle
A survey gives the following distribution:
Category Percentage
A25%
B20%
C30%
D15%
E10%

Find the angle corresponding to Category C.

30 × 3.6 = 108°
Answer: 108°
Problem 6 – Angle to Percentage
A sector in a pie chart subtends 72°. Find its percentage share.
Percentage = 72 / 3.6
Answer: 20%
Problem 7 – Angle to Actual Value
Total number of employees = 900.
Sector representing Department A = 120°.

Find the number of employees in Department A.
Employees = (120/360) × 900
= 300
Answer: 300 employees
Problem 8 – Actual Value to Total
In a pie chart, a 90° sector represents 250 students. Find the total number of students.

90° = 1/4 of complete circle.

Total = 250 × 4
Answer: 1000 students
⚡ Mental Calculation:

180° → 1/2 of total
120° → 1/3
90° → 1/4
72° → 1/5
60° → 1/6
45° → 1/8
36° → 1/10
Problem 9 – APPSC-Style Pie Chart Data Set
A pie chart shows 720 employees distributed among five departments:

A = 25%
B = 20%
C = 30%
D = 15%
E = 10%

Q1. Number of employees in Department B?

20% of 720 = 144
Answer: 144

Q2. Number of employees in Department C?

30% of 720 = 216
Answer: 216

Q3. Difference between A and D?

(25% − 15%) of 720 = 10% of 720 = 72
Answer: 72

Q4. Ratio C : E?

30 : 10 = 3 : 1
Answer: 3 : 1

Q5. Angle representing A + B?

25% + 20% = 45%
45 × 3.6 = 162°
Answer: 162°
PART–E: Histogram Numerical Problems
Problem 10 – Equal Class Intervals
Marks Frequency
0–105
10–2012
20–3018
30–4010
40–505

Which is the modal class?

Highest frequency = 18.

Answer: 20–30
⚡ Modal Class:

Class corresponding to the highest frequency.
Problem 11 – Unequal Class Intervals
Class Frequency Width Frequency Density
0–1010101
10–2020102
20–4030201.5
40–6020201
Frequency Density = Frequency / Class Width

Notice carefully:

20–40 has the highest raw frequency (30), but its density is only 1.5.

10–20 has density = 2.

Therefore, in the histogram based on unequal class widths, 10–20 has the greater rectangle height.
Problem 12 – Compare Histogram Heights
Class A: Width = 5, Frequency = 20
Class B: Width = 10, Frequency = 30

Which rectangle will be taller?

Class A:

20/5 = 4

Class B:

30/10 = 3
Answer: Class A is taller.
Exam Trap:

Higher frequency does not necessarily mean taller histogram rectangle when class widths are unequal.
PART–F: Frequency Polygon Problems
Problem 13 – Find Plotting Points
Class Frequency
0–104
10–208
20–3012
30–406

First calculate class marks:

Class Mark = (Lower Limit + Upper Limit)/2
Class Class Mark Frequency Plotting Point
0–1054(5,4)
10–20158(15,8)
20–302512(25,12)
30–40356(35,6)
⚡ Frequency Polygon:

X-coordinate → Class Mark
Y-coordinate → Frequency
Problem 14 – Reverse Class Mark Problem
A class has midpoint 35 and class width 10. Find the class interval.

Half width = 10/2 = 5.

Lower = 35 − 5 = 30
Upper = 35 + 5 = 40
Answer: 30–40
PART–G: Ogive Numerical Problems
Problem 15 – Frequency to Less-Than Cumulative Frequency
Class Frequency Less-Than C.F.
0–1055
10–20813
20–301225
30–401035
40–50540

Less-than ogive plotting points:

(10,5)
(20,13)
(30,25)
(40,35)
(50,40)
⚡ Less Than:

Use Upper Class Boundary/Limit
+ Less-Than Cumulative Frequency
Problem 16 – More-Than Cumulative Frequency

For the same distribution:

N = 40
More Than Cumulative Frequency
040
1035
2027
3015
405
500
⚡ More Than:

Start from N
and successively subtract frequencies.
Problem 17 – Recover Frequency from Ogive Data
Less-than cumulative frequencies are:

Less than 10 = 8
Less than 20 = 20
Less than 30 = 35
Less than 40 = 50

Find the frequency for class 20–30.
Frequency = 35 − 20
Answer: 15
⚡ Cumulative Frequency → Ordinary Frequency

Take successive differences.
Problem 18 – Median from Ogive Principle
Total frequency N = 80.
At what cumulative-frequency level should the median be located?
N/2 = 80/2 = 40
Answer: Locate cumulative frequency 40.
Graphically, the intersection of the Less-Than Ogive and More-Than Ogive gives the Median.
PART–H: Line Graph / Time-Series Problems
Problem 19 – Production Trend
Year Production
2021100
2022120
2023150
2024135
2025180

Q1. During which period did production decline?

Answer: 2023 → 2024

Q2. What was the decline?

150 − 135 = 15
Answer: 15 units

Q3. Percentage increase from 2021 to 2025?

(180 − 100)/100 × 100
Answer: 80%

Q4. Average production over five years?

(100 + 120 + 150 + 135 + 180)/5
685/5 = 137
Answer: 137 units
PART–I: Which Graph Should Be Used?
Given Data / Purpose Best Representation
Sales of five companies Simple Bar Diagram
Imports and exports over years Multiple Bar Diagram
Family expenditure components Component Bar / Pie Chart
Market shares totaling 100% Pie Chart
Continuous grouped frequencies Histogram
Frequency against class midpoint Frequency Polygon
Smooth frequency distribution Frequency Curve
Cumulative frequencies Ogive
Changes over time Arithmetic Line Graph
PART–J: APPSC Mixed Numerical Practice Set
Question 20
A pie-chart sector is 144°. What percentage does it represent?

A) 20%
B) 30%
C) 40%
D) 45%

144 ÷ 3.6 = 40
Answer: C – 40%
Question 21
If 40% in a pie chart represents 320 persons, find the total.
Total = 320 × 100/40
Answer: 800
Question 22
A sector of 60° represents 200 persons. How many persons does the complete circle represent?
60° = 1/6 circle
Total = 200 × 6 = 1200
Answer: 1200
Question 23
Class interval = 40–60 and frequency = 30. Find frequency density.
Width = 60 − 40 = 20
Density = 30/20 = 1.5
Answer: 1.5
Question 24
Frequency densities of two classes are:

Class A → 2.5
Class B → 3.5

Which histogram rectangle is taller?
Answer: Class B
Question 25
The class interval is 50–70. What is the class mark?
(50 + 70)/2 = 60
Answer: 60
Question 26
A frequency polygon contains the point (25, 18). What does 25 normally represent?

A) Frequency
B) Class Width
C) Class Midpoint
D) Cumulative Frequency

Answer: C – Class Midpoint
Question 27
Less-than cumulative frequencies are 6, 15, 27, 40. Find the frequency of the third class.
27 − 15 = 12
Answer: 12
Question 28
A distribution has N = 100. The less-than cumulative frequency up to a class is 65. How many observations lie above that point?
100 − 65 = 35
Answer: 35
Question 29
The intersection of less-than and more-than ogives gives:

A) Mean
B) Median
C) Mode
D) Variance

Answer: B – Median
Question 30
Which graph is particularly associated with graphical determination of mode?

A) Histogram
B) Pie chart
C) Ogive
D) Simple bar

Answer: A – Histogram
PART–K: Higher-Level APPSC Data Interpretation Set
The following data show the number of candidates appearing and qualifying in an examination:
Year Appeared Qualified
2021800200
20221000300
20231200360
20241500525
20251800720
Question 31 – Qualification Rate in 2021
200/800 × 100 = 25%
Answer: 25%
Question 32 – Qualification Rate in 2025
720/1800 × 100 = 40%
Answer: 40%
Question 33 – Increase in Qualified Candidates
720 − 200 = 520
Answer: 520
Question 34 – Percentage Increase in Qualified Candidates from 2021 to 2025
(720 − 200)/200 × 100
520/200 × 100 = 260%
Answer: 260%
Question 35 – Ratio of Appeared Candidates in 2022 and 2025
1000 : 1800 = 5 : 9
Answer: 5 : 9
Question 36 – Total Qualified Candidates
200 + 300 + 360 + 525 + 720 = 2105
Answer: 2105
PART–L: Tricky APPSC Questions
Question 37
Class A has frequency 40 and width 20.
Class B has frequency 30 and width 10.

Which class has greater histogram height?

A density:

40/20 = 2

B density:

30/10 = 3
Answer: Class B
Frequency A is greater, but histogram height B is greater.
Question 38
Two pie-chart sectors have angles 120° and 80°. Find the ratio of the quantities represented.
120 : 80 = 3 : 2
Answer: 3 : 2
⚡ Same Pie Chart:

Ratio of quantities = Ratio of sector angles.
Question 39
In a pie chart, A : B = 2 : 3. If sector A is 80°, find sector B.
2 : 3 = 80 : B
B = 120°
Answer: 120°
Question 40
A line graph value increases from 250 to 300. Find percentage increase.
Increase = 50
50/250 × 100 = 20%
Answer: 20%
PART–M: 10-Second Identification Questions
Clue in Question Think Immediately
Circle / Sector / Degrees Pie Chart
360° Complete Pie
Two series side-by-side Multiple Bar
Parts within same bar Component Bar
Continuous Classes + Rectangles Histogram
Unequal Class Widths Frequency Density
Class Midpoint + Frequency Frequency Polygon
Smooth Frequency Shape Frequency Curve
Cumulative Frequency Ogive
Less Than Upper Boundary
More Than Lower Boundary
Two Ogives Intersect Median
Graphical Mode Histogram
Year / Month / Time Trend Line Graph
PART–N: Formula Box for APPSC
Percentage
= Part / Total × 100

Percentage Increase
= (New − Old) / Old × 100

Percentage Decrease
= (Old − New) / Old × 100

Average
= Total / Number of Observations

Pie Sector Angle
= Component / Total × 360°

Pie Angle from Percentage
= Percentage × 3.6°

Percentage from Pie Angle
= Angle / 3.6

Component from Pie Angle
= Angle / 360 × Total

Class Mark
= (Lower + Upper)/2

Frequency Density
= Frequency / Class Width

Frequency from Cumulative Frequency
= Current C.F. − Previous C.F.

Median Position
= N/2
PART–O: Final APPSC Strategy
Step 1: Identify the graph type.

Step 2: Check what the axes/sectors represent.

Step 3: Note whether values are actual numbers, percentages or angles.

Step 4: Check total before calculating.

Step 5: For percentage change, always identify the original/base value.

Step 6: For a pie chart, immediately remember 360° = 100%.

Step 7: For unequal histogram classes, immediately check class width.

Step 8: For frequency polygon, calculate class marks.

Step 9: For ogive, first prepare cumulative frequencies.

Step 10: Simplify ratios before selecting the option.
చివరి నిమిషం పునశ్చరణ
Bar Graph → Difference, Ratio, Average, Percentage

Multiple Bar → Comparison of Two or More Series

Component Bar → Parts of Total

Pie Chart → 360° = 100%

1% → 3.6°

Histogram → Continuous Frequency Distribution

Unequal Classes → Frequency Density

Frequency Density → f / Class Width

Frequency Polygon → Class Mark + Frequency

Frequency Curve → Smooth Curve

Ogive → Cumulative Frequency

Less Than → Upper Limits

More Than → Lower Limits

Ogive Intersection → Median

Histogram → Mode Graphically

Line Graph → Trend Over Time

Most Important Numerical Areas:

Pie Chart Conversions
Percentage Change
Ratio & Average
Unequal-Width Histogram
Frequency Density
Cumulative Frequency
Ogive Interpretation
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